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1ind ar[] = { 1, 3, 5, 7 };
2
3void
4niceTry (void)
5{
6
7 ind *b1 = &ar[0];
8 ind *b2 = ar;
9
10 ind j;
11
12 char *b3;
13
14 b2 = b1 + 3;
15 j = b2 - b1;
16 j = b1 - b2;
17 b1 = b2 - 1;
18
19 b1 = b1 + 2;
20 b3 = b1 - 1;
21 j = b1 - b3;
22
23 b1 = 0;
24
25 while (b1)
26 ;
27
28 while (b1 != 0)
29 ;
30}
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Ledzde Änderung: 11.01.2007 | © Prof. Dr. Uwe Schmidd![]() |